x^2+3x-3-1=x^2-4

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Solution for x^2+3x-3-1=x^2-4 equation: 



x^2+3x-3-1=x^2-4

We move all terms to the left:

x^2+3x-3-1-(x^2-4)=0

We add all the numbers together, and all the variables

x^2+3x-(x^2-4)-4=0

We get rid of parentheses

x^2-x^2+3x+4-4=0

We add all the numbers together, and all the variables

3x=0

x=0/3

x=0

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